write an equation that is perpendicular to x 3y =3 and passes through
X 3Y 3 In Slope Intercept Form. Subtract from both sides of the equation. Here's how you'd do that:
Here's how you'd do that: Y = 1 3x+ 1 y = 1 3 x. 7x + 3y = 3 subtract 7x from both sides: Divide each term in by and simplify. Y = − 1 3x−1. Subtract from both sides of the equation. Subtract from both sides of the. Web the forms y=mx+b and y=mx+a are essentially the same, except for the naming of the constant term. Subtract from both sides of the. Level up on the above.
Y = mx + b. Y = 1 3x+ 1 y = 1 3 x. Here's how you'd do that: Subtract from both sides of the. Subtract from both sides of the. Divide each term in by and simplify. Level up on the above. Subtract from both sides of the equation. Y = − 1 3x−1. How do you find the slope and the y. Y = mx + b.
